20c^2-41ct+20t^2=0

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Solution for 20c^2-41ct+20t^2=0 equation: 


Simplifying
20c2 + -41ct + 20t2 = 0

Reorder the terms:
-41ct + 20c2 + 20t2 = 0

Solving
-41ct + 20c2 + 20t2 = 0

Solving for variable 'c'.

Factor a trinomial.
(4c + -5t)(5c + -4t) = 0


Subproblem 1
Set the factor '(4c + -5t)' equal to zero and attempt to solve:

Simplifying
4c + -5t = 0

Solving
4c + -5t = 0

Move all terms containing c to the left, all other terms to the right.

Add '5t' to each side of the equation.
4c + -5t + 5t = 0 + 5t

Combine like terms: -5t + 5t = 0
4c + 0 = 0 + 5t
4c = 0 + 5t
Remove the zero:
4c = 5t

Divide each side by '4'.
c = 1.25t

Simplifying
c = 1.25t

Subproblem 2
Set the factor '(5c + -4t)' equal to zero and attempt to solve:

Simplifying
5c + -4t = 0

Solving
5c + -4t = 0

Move all terms containing c to the left, all other terms to the right.

Add '4t' to each side of the equation.
5c + -4t + 4t = 0 + 4t

Combine like terms: -4t + 4t = 0
5c + 0 = 0 + 4t
5c = 0 + 4t
Remove the zero:
5c = 4t

Divide each side by '5'.
c = 0.8t

Simplifying
c = 0.8t
Solution
c = {1.25t, 0.8t}

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